50.1x^2-19.4x-1=0

Solution for 50.1x^2-19.4x-1=0 equation:

50.1x^2-19.4x-1=0

a = 50.1; b = -19.4; c = -1;
Δ = b2-4ac
Δ = -19.42-4·50.1·(-1)
Δ = 576.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19.4)-\sqrt{576.76}}{2*50.1}=\frac{19.4-\sqrt{576.76}}{100.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19.4)+\sqrt{576.76}}{2*50.1}=\frac{19.4+\sqrt{576.76}}{100.2}
$